Problem of the Day
Thursday, September 24, 2026
Problem:
The decimal number 237 is equivalent to the boolean number:
111111111011011111010111101011
The correct answer is b.
We can identify the boolean equivalent by subtracting out factors of 2, one at a time.
28 is 256, which is greater than 237, so let's start at one less than that:
- 27 = 128, which is less than 237, so we have
1"128" in our binary number. Subtract out the 128 to find that we still have 109 left to account for. - 26 = 64, which is less than 109, so we have
1"64" in our binary number. Subtract out 64 to find that we still have 45 to count. - 25 = 32, which is less than 45, so we have
1"32" in our binary number. Subtract out 32 from 45 to get 13. - 24 = 16, which is more than 13, so we have
0"16"s in our number. - 23 = 8, which is less than 13, so we have
1"8" in our number. Subtract 8 from 13 to get the remaining 5. - 22 = 4, which is less than 5, so we have
1"4" in our number. Subtract 4 from 5 to get 1. - 21 = 2, which is more than 1, so we have
0"2"s. - Finally, 20 = 1, which is what we have left, so we have
1"1" in our number.
Put it all together and the binary equivalent is 11101101.